Answer:
Planet A: Mars
Planet B: Earth
<em>Explanation</em>:
I got it right on Edge 2020, your welcome :)
B; An unshelled fish is lively and elusive past the power of words to portray, and in this, undoubtedly, lies its desirability.
Answer:
I think the third one......
Answer:
1. Isabella wanted
2.She read and reviewed
3.She constructed a hypothesis
4.She submitted her proposal
5.Control groups
6.She collected
7.She reached a conclusion
8.she presented
Explanation:
I got it right
Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.
![DF=\frac{Vi}{Vf}](https://tex.z-dn.net/?f=DF%3D%5Cfrac%7BVi%7D%7BVf%7D)
<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:
![345 µg = 0,345 mg](https://tex.z-dn.net/?f=345%20%C2%B5g%20%3D%200%2C345%20mg)
now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula
![DF= \frac{15mg protein/mL}{0.345mg protein/mL}](https://tex.z-dn.net/?f=DF%3D%20%5Cfrac%7B15mg%20protein%2FmL%7D%7B0.345mg%20protein%2FmL%7D)
![DF= 43,5 mg protein/ mL](https://tex.z-dn.net/?f=DF%3D%2043%2C5%20mg%20protein%2F%20mL)
Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL
![43,5mL-1,0mL = 42,5 mL](https://tex.z-dn.net/?f=43%2C5mL-1%2C0mL%20%3D%2042%2C5%20mL)
So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)