Answer:
hh7g;-=_47
Step-by-step explanation:
It's this answer because I guessed and I have no clue getNoozb
For this case we have to by definition:
1 kg equals 1000 grams
Shark 1:
405 kg and 68 grams
Thus, shark 1 weighs 405,068 grams.
Shark 2:
324 kg and 75 grams
Thus, shark 2 weighs 324,075 grams.
Subtracting we have:
Thus, shark 1 weighs 80,993 grams more than the second.
Answer:
Shark 1 weighs 80,993 grams more than the second.
Answer:
20) 30°; 21) 21,1; 22) 6,2
Step-by-step explanation:
For the first image, you have to do <em>csc</em><em>⁻</em><em>¹</em><em> </em><em>2</em><em> </em>[OR <em>sin</em><em>⁻</em><em>¹</em><em> </em><em>½</em>] because you are solving for an angle measure. When evaluated, you get 30°.
For the second image, you have to do <em>13sec</em><em> </em><em>52</em><em>°</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>[OR <em>13\</em><em>cos</em><em> </em><em>52</em><em>°</em><em> </em><em>= x</em>]. When evaluated, you get an approximate measure of 21,1.
For the third image, you have to do <em>6csc</em><em> </em><em>75</em><em>°</em><em> </em><em>=</em><em> </em><em>x</em><em> </em>[OR <em>6</em><em>\</em><em>sin</em><em> </em><em>75</em><em>°</em><em> </em><em>= x</em>]. When evaluated, you get an approximate measure of 6,2.
Extended information on Trigonometric Ratios
O\H = sin θ
A\H = cos θ
O\A = tan θ
H\A = sec θ
H\O = csc θ
A\O = cot θ
I am joyous to assist you anytime.
let's label each pump A, B, and C, just for convenience. A fills the tank by 1/50 every minute, B fills the tank by 1/60 every minute, and C drains it by 1/75 every minute. Now we can put them all into one function: t(1/50 + 1/60 - 1/75) = 1, where t = our time in minutes and 1 = the tank being full.
next, we solve for t: t = 300/7 minutes, or approximately 42.86 minutes.
Answer:
12
Step-by-step explanation:
we can see that the base's size is doubled, from that we can find that 6 will be doubled to twelve.
