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lubasha [3.4K]
3 years ago
9

Can anyone help me with this question please:

Mathematics
1 answer:
ladessa [460]3 years ago
3 0
The problem is asking us to isolate B. The given equation is solved for P, and we need to rearrange it for B.

First we need to square both sides. This will cancel out the square root on the right side.

P^2 = E + A^2/B^2

Next, subtract E from both sides.

P^2 - E = A^2/B^2

Next we need to get the B^2 out of the denominator. Multiply both sides by B^2.

B^2(P^2 - E) = A^2

Next divide both sides by (P^2 - E).

B^2 = A^2/(P^2 - E)

Lastly, take the square root of both sides.

B = sqrt(A^2/(P^2 - E))








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13. Jessica has taken 8 quizzes. The mean of her scores is 92. Her first 6 scores are shown.
Dovator [93]

Answer: Median= 91; 8th quiz score=86

Step-by-step explanation: The sum of the scores is 8×92=736. Subtract the 6 given scores and then a 100 for the seventh quiz to find the score she got on the 8th quiz, this is an 86. Now that you have all the scores, arrange them all in the least to greatest order and find the average of the middle two numbers (median), which is 91!

7 0
3 years ago
If four tires can be changed in 3/4 of an hour gow long would it take to change 19 cars​
kobusy [5.1K]

Answer:

14.25 hours

Step-by-step explanation:

Four tires = 3/4 of an hour

=> 1 car = 3/4 of an hour

=> 19 cars = ?

=> If 1 = 3/4

=> 19 = 3/4 x 19

=> 3/4 x 19

=> 57/4

=> 14.25 hours

So, it would take 14.25 hours for 19 car's tires to be changed.

5 0
3 years ago
Multiply and simplify: 3a(4a2 – 5a + 12)
DochEvi [55]
3a(4a²-5a+12)

12a³-15a²+36a

~Hope this helped!~
3 0
3 years ago
A local University accepted 2,300 students out of 4,500 applicants for admission. What was the acceptance rate, expressed as a p
Mademuasel [1]
2300 out of 4500 were chosen

2300 / 4500 = 0.5111

0.51 = 51%

51% is the acceptance rate.
4 0
3 years ago
Read 2 more answers
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
3 years ago
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