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Alenkinab [10]
3 years ago
15

Sheldon wants to buy a laptop that costs $ 450 from an electronics store . He has two coupons to choose from coupon A which give

s him a $ 80 discount and coupon B which gives him a discount of 20.5 % off . Which coupon gives him the better buy ?
Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

Coupon B

Step-by-step explanation:

Given

Price = \$450

Coupon\ A = \$80

Coupon\ B = 20.5\%

Required

Which coupon is better

From the question, we have:

Coupon\ A = \$80

Coupon\ B = 20.5\%

Coupon B means that:

Coupon\ B = 20.5\% * \$450

Coupon\ B = 0.205 * \$450

Coupon\ B = \$92.25

By comparison:

Coupon B gives him a better buy because: \$92.25 > \$80

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Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
4 = 1 - n + 4? Geometry btw
eimsori [14]

Answer:

N = -7

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Then rearrange the terms

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The you add 3 to both sides of the equations

4 + 3 = -n - 3 + 3

3 0
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