Answer:
A , 210.3 g
Explanation:
Given data:
Number of moles of SiO₂ = 3.50 mol
Mass of SiO₂ = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of SiO₂ = 60.08 g/mol
by putting values,
3.50 mol = mass/60.08 g/mol
Mass = 3.50 mol × 60.08 g/mol
Mass = 210.3 g
Answer:
Blues
Explanation:
Colors of Rainbow => ROYGBIV
Red Orange Yellow Green Blue Indigo Violet
low energy => => => => => => => => => => high energy
low frequency => => => => => => => => => high frequency
long wavelengths => => => => => => => => short wavelengths
Note: All L's on the Left => low, low, long; other end are opposites.
Through ratio and proportion, for every mole of O2, there is also a mole equivalent of CO2. In this case, we divide first 8.94 g O2 by 32 g/mol to convert the mass to mole. That is equivalent to 0.279375 mol which is also the amount of CO2. Multiplied by 44g/mol which is the molar mass of CO2, the answer is 12.29 grams CO2.
Answer:
312 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.
Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:
Mole of O₂ = 9.75 moles
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mole = mass / Molar mass
9.75 = Mass of O₂ / 32
Cross multiply
Mass of O₂ = 9.75 × 32
Mass of O₂ = 312 g
Thus, 312 g of O₂ were obtained from the reaction.