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3 years ago

Someone please help me with the second question ONLY

Chemistry

1 answer:

wlad13 [49]3 years ago

4 0

Answer:

Explanation:

this experiment could not be replicated, because there are no specific measurements. the details would not be the same because it does not include the type of paper used nor the diameter, width or length. A guess of the measurements would be the only way to replicate this experiment but other then that, no you cannot.

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HELP 15-21 PLEASE!!!

Harlamova29_29 [7]

Answer:

15. Lead (II) chloride

16. potassium chloride

17. Lithium oxide

18. Arsenious trioxide

19.Phosphorus tribromide

Explanation:

6 0

3 years ago

Read 2 more answers

A student experimentally obtained the density of osmium the densest element as 22.57g/cm3 the density of osmium is reported to b

Airida [17]

Answer:

The answer to your question is: % error = 0.4

Explanation:

Data

real value = 22.48%

estimated value = 22.57 %

Formula

% error = |real value - estimated value|/real value x 100

%error = |22.48 - 22.57|/22.48 x 100

% error = |-0.09|/22.48 x 100

%error = 0.09/22.48 x 100

% error = 0.004 x 100

% error = 0.4

3 0

4 years ago

You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0

3 years ago

1. Matter can be measured in many ways for specific purposes. Which measurement depends on the force of gravity it is not reliab

Ganezh [65]

Answer:

1. B- weight

2. B- 2.0g/cm3

3. C- 22.8g/cm3

Explanation:

6 0

3 years ago

Summarize atomic radius

beks73 [17]

Atomic radius is determined as the distance between the nuclei of two identical atoms bonded together. The atomic radius of atoms generally decreases from left to right across a period.

8 0

3 years ago