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Elena-2011 [213]
3 years ago
5

If a weak monoprotic acid, HA, is titrated with strong base, what is NOT true at the half equivalence point?pH = pKapH = 7.0[HA]

= [A-]Buffer capacity is maximized
Mathematics
1 answer:
leonid [27]3 years ago
6 0

Answer:

pH can be different from 7 ( second statement is false)

Step-by-step explanation:

since

pH=pKa + log [A-]/[HA]

at half of the equivalence point

[HA]= [A-] (third statement is true)

and therefore

pH = pKa (first statement is true)

since pH = pKa , pH can be different from 7 ( second statement is false)

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The sum of two numbers is 6, their difference is 4, find the two numbers. What is their product?
Firlakuza [10]

Answer:

The two numbers are 5 and 1. Their product is 5

Step-by-step explanation:

x + y = 6 (*)

x - y = 4 (**)

Let (*) + (**)

--> (x+y) + (x-y) = 6 + 4

<=> 2x = 10 <=> x = 5

Substitute x= 5

(*) <=> 5 + y = 6

<=> y=1

Answer: (x,y) = (5,1)

Their product: x.y = 5x1 = 5

6 0
3 years ago
Fourteen more than three times a number is the
Radda [10]

Answer:

14+3*x = 10-6*x

Step-by-step explanation:fourteen more means 14+ 3 times a number means 3 multiplied by a number x is the number of your choice and 10 less means 10 - and 6 times the number means 6*x

6 0
3 years ago
Please help!!!!!!!!!
kotykmax [81]

10+6+9+13+7= 45

and divide it by 5

the answer is 9

8 0
3 years ago
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Dahasolnce [82]
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57 over 38 minus 1,00
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3 years ago
Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom
IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0
3 years ago
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