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liq [111]
4 years ago
11

A centipede is crawling 6 inches per minute. how long will it take the centipede to travel 1 yard?

Mathematics
1 answer:
Ede4ka [16]4 years ago
3 0
6 minutes, because 1 yd is equivalent to 3 feet, which is equivalent to 36 inches.  If a centipede crawls at 6 inches per minute, you do 6 x 6, which equals 36, and get 6 minutes!
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Is 11/12 less that or greater than 1/2
Kryger [21]

Answer:

11/12 is greater than 1/2.

Step-by-step explanation:

We can make them have a common denominator of 12 to compare:

11/12 = 11/12

1/2 = 6/12.

So from this, we can see that 11/12 > 6/12.

6 0
3 years ago
Read 2 more answers
Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim
geniusboy [140]

Answer:

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

The answer of the above definite integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98

Step-by-step explanation:

The given limit interval is

\lim_{||\Delta|| \to 0}  \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i

[a, b] =  [-8, 6]

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x

Bonus:

The definite integral may be solved as

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98

Therefore, the answer to the integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x  = 98

5 0
3 years ago
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Anettt [7]

Answer:

Hi! The correct answer is x=b^2/c, c=b^2/x

Step-by-step explanation:

<em><u>~Solve the rational equation by combining expressions and isolating the variable c and b~  </u></em>

6 0
3 years ago
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natulia [17]

Answer:

x=59

Step-by-step explanation:

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Answer:

D.

Bob should use the mean to make his selling price look like it's the greatest.

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