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elixir [45]
3 years ago
9

​User documentation _____. Group of answer choices ​allows users to prepare overall documentation, such as process descriptions

and report layouts, early in the software development life cycle (SDLC) ​describes a system’s functions and how they are implemented ​contains all the information needed for users to process and distribute online and printed output ​consists of instructions and information to users who will interact with the system
Computers and Technology
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

And user documentation consists of instructions and information to users who will interact with the system

Explanation:

user documentation will not allow user to prepare overall documentation because it is already prepared so not A.

user documentation does not need implementation, So not B.

user documentation may not be a printed one . So not C

And user documentation consists of instructions and information to users who will interact with the system, so D is the right option

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Although some media critics disagree about the terminology, smartphones and other mobile devices used to watch content originall
GuDViN [60]

Answer:

The correct answer to the following question will be Fourth screens.

Explanation:

In marketing communication and in advertising, fourth screen can be referred to video screen which are small portable such as, smartphones, portable media player and other mobile devices. This type of screen also used to watch those content which are reserved for TV.

Today most of the people use mobile devices for such tasks. Sometimes the third screen also refers for the opening of new possibilities but fourth will widely have used.

Hence, option C is the correct answer.

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Answer:

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Explanation:

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3 years ago
Who was the chief justice of the Supreme Court during the Scott v. Sandford case? John Brown Roger
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The correct answer is Roger B. Taney. Roger B. Taney is the chief justice of the Supreme Court during the Scott v. Sandford case. The Scott v. Sandford case <span>was a </span>landmark decision<span> by the </span>U.S. Supreme Court<span> in which the Court held that "a negro, whose ancestors were imported into the US and sold as slaves"</span>
6 0
3 years ago
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Write a program that allows the user to enter the last names of five candidates in a local election and the number of votes rece
amm1812

Answer:

a= input("Enter the last name of first candidate: ")

aVotes= int(input("Enter Number of votes cast for "+ a + ": "))

b= input("Enter the last name of second candidate: ")

bVotes= int(input("Enter Number of votes cast for "+ b + ": "))

c= input("Enter the last name of third candidate: ")

cVotes= int(input("Enter Number of votes cast for "+ c + ": "))

d= input("Enter the last name of fourth candidate: ")

dVotes = int(input("Enter Number of votes cast for "+ d + ": "))

e= input("Enter the last name of fifth candidate: ")

eVotes = int(input("Enter Number of votes cast for "+ e + ": "))

votes= [aVotes,bVotes,cVotes,dVotes,eVotes]

aPercent= (round((aVotes/sum(votes))*100, 2))

bPercent= (round((bVotes/sum(votes))*100, 2))

cPercent= (round((cVotes/sum(votes))*100, 2))

dPercent= (round((dVotes/sum(votes))*100, 2))

ePercent= (round((eVotes/sum(votes))*100, 2))

print( a, ":", aVotes,"Votes", aPercent,"%")

print( b, ":", bVotes,"Votes", bPercent,"%")

print( c, ":", cVotes,"Votes", cPercent,"%")

print( d, ":", dVotes,"Votes", dPercent,"%")

print( e, ":", eVotes,"Votes", ePercent,"%")

winner= max(votes)

if winner==aVotes:

   print(a," is the Winner")

elif winner==bVotes:

   print(b," is the Winner")

elif winner==cVotes:

   print(c," is the Winner")

elif winner==dVotes:

   print(d," is the Winner")

elif winner==eVotes:

   print(e," is the Winner")

else:

   None

Explanation:

  • First section

<em> a= input("Enter the last name of first candidate: ") </em>

<em>aVotes= int(input("Enter Number of votes cast for "+ a + ": ")) </em>

<em>b= input("Enter the last name of second candidate: ") </em>

<em>bVotes= int(input("Enter Number of votes cast for "+ b + ": ")) </em>

<em>c= input("Enter the last name of third candidate: ") </em>

<em>cVotes= int(input("Enter Number of votes cast for "+ c + ": ")) </em>

<em>d= input("Enter the last name of fourth candidate: ") </em>

<em>dVotes = int(input("Enter Number of votes cast for "+ d + ": ")) </em>

<em>e= input("Enter the last name of fifth candidate: ") </em>

<em>eVotes = int(input("Enter Number of votes cast for "+ e + ": ")) </em>

Collects the last name and the number of  votes cast

  • Second section

<em>votes= [aVotes,bVotes,cVotes,dVotes,eVotes] </em>

<em />

places all the votes in a list.

The reason for this is to allow us use the "sum function" and "max function", to get the sum of all the votes.

  • Third section

<em>aPercent= (round((aVotes/sum(votes))*100, 2)) </em>

<em>bPercent= (round((bVotes/sum(votes))*100, 2)) </em>

<em>cPercent= (round((cVotes/sum(votes))*100, 2)) </em>

<em>dPercent= (round((dVotes/sum(votes))*100, 2)) </em>

<em>ePercent= (round((eVotes/sum(votes))*100, 2)) </em>

calculates the percentage of all the votes cast for the individual candidates

  • Fourth section

<em>print( a, ":", aVotes,"Votes", aPercent,"%") </em>

<em>print( b, ":", bVotes,"Votes", bPercent,"%") </em>

<em>print( c, ":", cVotes,"Votes", cPercent,"%") </em>

<em>print( d, ":", dVotes,"Votes", dPercent,"%") </em>

<em>print( e, ":", eVotes,"Votes", ePercent,"%") </em>

prints out the candidates name, number of votes received and the percentage

  • Fifth section

winner= max(votes)

gets the maximum votes cast

  • Sixth Section

if winner==aVotes:

   print(a," is the Winner")

elif winner==bVotes:

   print(b," is the Winner")

elif winner==cVotes:

   print(c," is the Winner")

elif winner==dVotes:

   print(d," is the Winner")

elif winner==eVotes:

   print(e," is the Winner")

else:

   None

uses if statements to compare the maximum votes with the votes gotten by all the candidates to get a winner

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3 years ago
Anyone watch anime what's y'all race
slava [35]

Answer:

I do

Explanation:

I watch jojos bazaar adventure

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