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elixir [45]
3 years ago
9

​User documentation _____. Group of answer choices ​allows users to prepare overall documentation, such as process descriptions

and report layouts, early in the software development life cycle (SDLC) ​describes a system’s functions and how they are implemented ​contains all the information needed for users to process and distribute online and printed output ​consists of instructions and information to users who will interact with the system
Computers and Technology
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

And user documentation consists of instructions and information to users who will interact with the system

Explanation:

user documentation will not allow user to prepare overall documentation because it is already prepared so not A.

user documentation does not need implementation, So not B.

user documentation may not be a printed one . So not C

And user documentation consists of instructions and information to users who will interact with the system, so D is the right option

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Write a recursive method called lengthOfLongestSubsequence(a, b) that calculates the length of the longest common subsequence (l
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Explanation:

The following code is written in Java and creates the recursive function to find the longest common substring as requested.

 static int lengthOfLongestSubsequence(String X, String Y) {

       int m = X.length();

       int n = Y.length();

       if (m == 0 || n == 0) {

           return 0;

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           return 1 + lengthOfLongestSubsequence(X, Y);

       } else {

           return Math.max(lengthOfLongestSubsequence(X, Y),

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Answer:

See explanation below

Explanation:

Previos concepts

First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".

Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".

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Solution for the problem

Assuming the dataset given on the plot attached.

Part a

For this algorithm the result would be:

Job A   0-6

Job B   6-(6+3) = 6-9

Job C   9-(9+1) = 9-10

Job D   10-(10+4) = 10-14

Part b

For this algorithm the result would be:

Job A   0-6

Job C   6-(6+1) = 6-7

Job B   7-(7+3) = 7-10

Job D   10-(10+4) = 10-14

Part c

For this algorithm the result would be:

Job A   0-1  until 14

Job B   2-(2+3) = 2-5

Job C   3-(3+2) = 3-5

Job D   9-(9+5) = 9-14

Part d

For this algorithm the result would be:

Job A   0-2 , 7-9, 12-14

Job B   2-4, 9-10

Job C   4-(4+1) = 4-5

Job D   5-7, 10-12

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