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Bas_tet [7]
3 years ago
13

Corey wrote a code that will display his name every time he presses the down arrow key but there is a bug in it. Display letter

C, show letter O, show letter R, show letter E, show letter Y. What is the error in this algorithm?
Change the word "show" to "type."
Add when right mouse button pressed.
The letters O and R must be switched.
There is no loop in the code.
Computers and Technology
1 answer:
brilliants [131]3 years ago
7 0

Answer:

Explanation:

display letter c, type letter r, type letter o, type letter 3, type letter y- i think thats it but i dee cay this is confusing

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The user must specify the programming language he or she wants to use.

Explanation:

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A computer has two different printers that the computer can print to, what do you need in order
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Download and install a third-party printer application.

Explanation:

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In this assignment, you will create a flashcard app for teaching addition and multiplication. The student will choose the type o
Anna11 [10]

Answer:

See explaination

Explanation:

import java.util.*;

import java.lang.Math;

public class Main

{

public static double getRandomDoubleBetweenRange (double min, double max)

{

double x = (Math.random () * ((max - min) + 1)) + min;

return x;

}

public static void main (String[]args)

{

int option, number_of_problems, correct_answer;

double max_operand, average =

0, user_answer, sum, first_number, second_number, multiply,

sum_or_multiply;

Scanner user_input = new Scanner (System.in);

do

{

System.out.println

("Choose the type of problem: \n1. Addition \n2. Multiplication \n3. Mixed \n4. Quit");

option = user_input.nextInt ();

switch (option)

{

case 1:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum = first_number + second_number;

if (sum == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

sum);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 2:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

multiply = first_number * second_number;

if (multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

multiply);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 3:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 1; i <= number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

if (i % 2 == 1)

{

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number + second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

else

{

System.out.println (first_number + " * " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number * second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

out.println ("Incorrect, The Correct answer is " +

sum_or_multiply);

}

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 4:

System.out.println ("Thanks for playing.");

break;

default:

System.out.println ("Please choose a valid option");

break;

}

}

while (option != 4);

}

}

3 0
3 years ago
Write code that prints: Ready! firstNumber ... 2 1 Run! Your code should contain a for loop. Print a newline after each number a
Citrus2011 [14]

Answer:

The program to this question can be describes as follows:

Program:

#include <stdio.h> //defining header file

int main() //defining main method

{

int n,i,x=0; //defining integer variable

printf("Enter a number: "); //print message

scanf("%d",&n); //input value from the user  

printf("%d\n",n); //print input value

for(i=1;i<n;i++)  //loop to count reverse number

{

x=n-i; //calculate value

printf("%d\n",x);  //print value

}

return 0;

}

Output:

Enter a number: 3

3

2

1

Explanation:

  • In the above program, three integer variable "n,i and x" is declared, in which variable n we take input from the user end and the variable i and x is used in the loop to calculate the value in the reverse order.
  • In the next step, a loop is declared, in which the variable x calculates the value in reverse order and uses a print method to print its value.  
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3 years ago
How should you handle cyberbullies?
damaskus [11]

Answer:

insult those son of a bishes backk

8 0
3 years ago
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