Hello from MrBillDoesMath!
Answer:
One solution (z = -1)
Discussion:
-2(z+3)-z=-z-4(z+2) =>
-2z -6 -z = -z -4z - 8 =>
-3z -6 = -5z -8 => add 6 to both sides
-2z = -5z -2 => add 5z to both sides
3z = -5z +5z -3 =>
3z = -3 =>
z = -1
Thank you,
MrB
Answer:
-1/18
Step-by-step explanation:
What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3
Answer:
You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.
The probability of selecting a red marble the first time is 1313.
(This is because 4 out of 12 marbles are red and412412 reduces to 1313.
The probability of selecting a red marble the second time is 1313.
The marble selections are independent and you can multiply the two probabilities to get the following:
probability of getting 2 reds = (13)2(13)2
=19=19.
So the probability of getting two reds is 1919.