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Lady_Fox [76]
3 years ago
12

Will give crown will post one more

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0

Answer:

1 is 22; 2 is 19; 3 is 16; 4 is 13; 5 is 10

Step-by-step explanation:

Give me that crown again

Oksi-84 [34.3K]3 years ago
3 0

Answer:

22, 19, 16, 10

Step-by-step explanation:

y = 25-(3*1)= 22

y = 25-(3*2)= 19

y = 25-(3*3)= 16

y = 25-(3*5)= 10

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Are the expressions equivalent 7y + 21 and 3(2y+7)+y
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Answer:

Yes

Step-by-step explanation:

3(2y + 7) + y

6y + 21 + y

7y + 21

4 0
3 years ago
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KIM [24]

hi my name is afsshenn I am stealing your points hahaha

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2 years ago
Graph the linear equation 7x+4y=-28
Mashutka [201]

Answer:F

Step-by-step explanation:

4 0
3 years ago
Find the sum of the arithmetic sequence 1, 3, 5, 7, … , 99.
bezimeni [28]

The sum of the arithmetic sequence 1, 3, 5, 7, … , 99 is 2525

<h3>What is Sequence?</h3>

Sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

Given sequence is 1, 3, 5, 7, … , 99.

It is a arithmetic sequence, the difference between two consecutive terms will be same

d=3-1=2

first term a=1

l=last term =99

We need to find 99 is which term in the sequence

Aₙ = a + ( n - 1 ) d

99=1+(n-1)2

99=1+2n-2

99=2n-1

100=2n

Divide both sides by 2

50=n

Now we need to find the sum of 50 terms

Sₙ=n/2(l+d)

=50/2(99+2)

=25(101)

=2525

Hence, the sum of the arithmetic sequence 1, 3, 5, 7, … , 99 is 2525

To learn more on Sequence click:

brainly.com/question/21961097

#SPJ1

6 0
1 year ago
Forty-five roses, plus some number of daffodils and tulips, are blooming in a garden.
stellarik [79]

The maximum number of of bouquets the gardener could have made is 3

<h3>How to find unknown parameter</h3>

Total = 45

let

  • number of daffodils = x
  • number of tulips = y

Roses = 4x

Tulips = 4x + 15

Total = roses + daffodils + tulips

45 = 4x + x + (4x + 15)

45 = 5x + 4x + 15

45 = 9x + 15

45 - 15 = 9x

30 = 9x

x = 30/9

x = 3.33333333333333

Approximately,

x = 3

Let more about equation:

brainly.com/question/16863577

4 0
2 years ago
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