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Vedmedyk [2.9K]
3 years ago
11

1. Are the graphs of y = 3x - 2 and y = - 3x + 2 parallel, coinciding, perpendicular

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

none of these

Step-by-step explanation:

they do not have the same slope to be parallel, do not have the same slope or y intercept to be coinciding, and the product of the slopes of the two lines do not equal to -1. As a result, the two lines are not perpendicular to each other.

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This isnt a inequality
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Hi there!

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aliina [53]
y=x(x-2)^2
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Then the shaded region has area

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I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

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This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
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The volume is 448 mm^3

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