The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
The trigonometric function that can be used to find the value of x is 12 / tan ( 25 ) . The correct values of a and b will be 12 and 25 resp . .
Given :
A right angle triangle , one angle = 25 ° and side opposite given angle = 12 units .
Trigonometric Formula for Tan θ
tan θ = perpendicular / base , tan θ = ( sin θ / cos θ ) , tan θ = ( 1 / cot θ ) .
where θ = 25 , perpendicular = 12 , base = x .
Substituting values in above first formula ,
tan 25 = 12 / x
Therefore , x = 12 / tan ( 25 ) .
Hence , a = 12 and b = 25 .
To know more on trigonometry :
brainly.com/question/27998034
#SPJ4
The trick to solving this problem is to know and remember that the sum of all the interior angles of a triangle is always 180 degrees.
Thus, (6x+1) + (5x-17) + (9x-24) = 180.
20x = -40, so x = -2 (answer)
Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC = 
≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
= 
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA = 
, then
∠ A = 
( ) ≈ 66.9°
Answer:
Step-by-step explanation:
