Answer:

Step-by-step explanation:
What is the cube root of
? This is the question.
We can write:
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
We will use the below property to simplify:
![\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%2Ab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D)
So, we have:
![\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D)
We will now use below property to further simplify:
![\sqrt[n]{x} =x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Thus, we have:
![\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D%20%3D3%2A%28a%5E%7B12%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We know power to the power rule: 
Now, we have:

This is the correct answer: 
Answer:
400
Step-by-step explanation:
He makes $4 per shirt ($12-$8). $1600/4 = 400. So he woud need to see at least 400 shirts to break even.
-2 could not be the answer to |2x - 0.6| because it would have to be positive due to the “| |” symbols.
Answer:The answer will be 20
Step-by-step explanation: If you are given the circumference of something all you have to do is divide it my pi (3.14) to get the answer. If you know the diameter and is looking for the circumference you multiply the diameter by pi. Hope this helps.
Answer:
The volume of the triangular pyramid
V = 566.66 in³
Step-by-step explanation:
<u><em>Step(i):-</em></u>
The volume of the triangular pyramid

Base area = Area of the triangle

Given the base of the triangle (b) = 17in
Given Height of the triangle (h ) =10 in

The base area of the pyramid ( A) = 85 in²
<u><em>Step(ii):-</em></u>
<u><em>Given the height of the pyramid (h) = 20in</em></u>
The volume of the triangular pyramid

The volume of the triangular pyramid
=
<u><em>Final answer:-</em></u>
The volume of the triangular pyramid
V = 566.66 in³