Question

Which is the 6th term of the geometric sequence 729,81,9,

Answer 1

Answer:

$\frac{1}{81}$

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a$(r)^{n-1}$

where a is the first term and r the common ratio

r = $\frac{81}{729}$ = $\frac{9}{81}$ = $\frac{1}{9}$

and a = 729, hence

$a_{6}$ = 729 × $(\frac{1}{9}) ^{5}$

                        = 729 × $\frac{1}{59049}$ = $\frac{729}{59049}$ = $\frac{1}{81}$

Answer 2

Answer:

531,441 or 1/81

Step-by-step explanation:

You get this answer by multiplying each term by 9. for example: 9x9 is 81 and 81x9 is 729.

Unless this is going backwords and its division. Then the answer will be 1/81.