Consider the following equation f(x)=(x^2+4)/(4x^2-4x-8)
2 answers:
Answer: x=-1 and x=2 because (this is where the function is undefined) name of horizontal asymptote (y=1/4) because (m=n)
Step-by-step explanation: on edge
<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation


Thus the vertical asymptotes are x = - 1 and x = 2
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