Answer:
Step-by-step explanation:
First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.
Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).
Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.
Explanation:
When the inequality symbol is replaced by an equal sign, the resulting linear equation is the boundary of the solution space of the inequality. Whether that boundary is included in the solution region or not depends on the inequality symbol.
The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.
When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.
Once the boundary line is graphed, the half-plane that makes up the solution space is shaded. The shaded half-plane will be to the right or above the boundary line if the inequality can be structured to be of one of these forms:
- x > ... or x ≥ ... ⇒ shading is to the right of the boundary
- y > ... or y ≥ ... ⇒ shading is above the boundary
Otherwise, the shaded solution space will be below or to the left of the boundary line.
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Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.
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The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.
Its a type of thermal expansion and described by fractions that represents the fractional increase length of a thin beam of a material exposed to its temperature increase of one degree celcious,"
Given:
Carrie has 180 ft of the fencing and wishes the fence to be 4times as long as it is wide.
To Find:
The area in square feet that the fencing encloses.
Answer:
The fence encloses 3600 sq ft.
Step-by-step explanation:
Let x denote the length of the dog run and y denote the width of the dog run.
Given that the garage wall serves as one side of the dog run, we are left with 3 other sides to instal the fence.
Carrie has 180ft of fencing with her, so the sum of the lengths of the 3 sides has to be equal to 180. We can represent this in the form of an equation as

We are also given that Carrie wishes the fence to be 4 times as long as it is wide.
So,

Replacing this value into the first equation, we have

Therefore,

Thus, the length of the dog run is 120ft and the width is 30ft.
The area enclosed will be equal to the length multiplied with the width. So,

The fence encloses 3600 sq ft.
Answer:
i think its cancellation the others don't make sense.
Step-by-step explanation: