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Stels [109]
2 years ago
15

Write a leniar equadion to represent the situation below. The total ticket recipts for a play with $4 admotion for students and

$8 admitions for adults if there were 60 more student tickets sold than adult tickets.
Mathematics
1 answer:
Korvikt [17]2 years ago
7 0

Answer:

Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

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The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

7 0
3 years ago
Read 2 more answers
A paper is 0.55 mm thick. How high pile of 274 sheets? The paper is 24.5 long and 18.5 cm wide. Calculate volume of the pile of
strojnjashka [21]

The height of the pile is 150.7 mm, and the volume is V = 6,830,477.5 mm³.

<h3>How high will be the pile of papers?</h3>

We know that each paper is 0.55mm thick, then if we pile 274 of these, the height of the pile will be:

H = 0.55mm*274 = 150.7mm

Now we want to get the volume of the pile of paper. Remember that for a rectangular prism of height H, width W, and length L, the volume is:

V = H*W*L

In this case, we have:

  • H = 150.7mm
  • W = 18.5 cm = 185 mm
  • L = 24.5 cm = 245 mm

Then the volume is:

V = (150.7mm)*(185 mm)*(245 mm) = 6,830,477.5 mm³

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

5 0
1 year ago
12+[ 9 4/5 - ( 1.5 + 2 2/10)]<br><br><br><br>Someone please help me?​
lord [1]

Answer:

18.1

<em>The thing You NEEDED to do</em>

<h3><u>Simplify</u> or <u>Evaluate</u> Your Answer</h3>
5 0
3 years ago
Plsss help me !!!!
Yuri [45]

Answer:

The enrollment after 5 years is 10,724

Step-by-step explanation:

Generally, we can have the depreciation formula written as follows;

A = P(1 - r)^t

A is the number of enrollment in after a certain number of years t

P is the initial population which is 13,500

r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045

t = 5 years

Substituting these values, we have it that;

A = 13,500(1-0.045)^5

A = 10,723.84

4 0
2 years ago
Let's consider the time as a discrete variable with an increment of 1 minute. You arrive at a bus stop at 10 AM, knowing that th
Dafna11 [192]

Answer:

a) 2/3

b) 1/3

Step-by-step explanation:

Let X be the random event that measures the time you will have to wait.  

Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute

P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.

a)

P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3

b)

P(10 <  X ≤ 20) = (20-10)/30 = 1/3

7 0
2 years ago
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