Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
Answer:
BD is half of the answer BF is
Step-by-step explanation:
BD is only half of BF so find the answer for BF and then divide by @ and you have your answer.
Answer:
384π
Step-by-step explanation:
From the diagram,
Diameter ( d ) = 16
Height ( h ) = 16
To find : Surface area of Cylinder = ?
Radius ( r ) = ?
Formula : -
r = d / 2
r = 16 / 2
r = 8
Formula : -
Surface area of Cylinder = 2πr ( r + h )
Surface area of Cylinder = 2πr ( r + h )
= 2π x 8 ( 8 + 16 )
= 16π x 24
Surface area of Cylinder = 384π
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
