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tatiyna
3 years ago
14

Rewrite each expression without parentheses:

Mathematics
2 answers:
Luda [366]3 years ago
3 0

Answer:

4-3+x

-12+4x

sorry if this isnt right :P

jarptica [38.1K]3 years ago
3 0

Answer:

Step-by-step explanation:

4-(3-x)=

4-3+x

1+x

4(-3+x)

-12+4x

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Find the geometric mean of 8 and 253.
sveta [45]

The geometric mean of 8 and 253 is;

<h3>Geometric mean of numbers</h3>

According to the question;

  • The task requires that the geometric mean of 8 and 253 be determined.

The geometric mean of a two numbers is the square root the product of the he numbers.

Hence, in this scenario;

The geometric mean of 8 and 253 is;

  • G.M = √8×253

  • G.M = √2024

G.M = 45.

Ultimately, the geometric mean of 8 and 253 is approximately 45.

Read more on geometric mean;

brainly.com/question/23483761

5 0
2 years ago
Use the rules of exponents to evaluate and simplify the following expression. Type all without negative exponents. Do not distri
Rainbow [258]

We are given (xy)^(-3).

This leads to 1/(xy)^3.

You see, going from the top to the bottom alters the sign of the exponent to its opposite.

ANSWER: 1/(x^3•y^3)

Did you follow?

5 0
3 years ago
What is the surface area of the figure shown? Plz answer asap
Luba_88 [7]

Answer:

264\ cm^{2}

Step-by-step explanation:

we know that

The surface area of the figure is equal to the lateral face of the triangular pyramid plus the lateral face of the rectangular prism plus the area of the base of the rectangular prism

step 1

Find the lateral face of the triangular prism

The lateral area is equal to the area of its four lateral triangular faces

LA=4(\frac{1}{2}(6)(7))=84\ cm^{2}

step 2

Find the lateral area of the rectangular prism

The lateral area is equal to the perimeter of the base multiplied by the height

LA=(4)(6)(6)=144\ cm^{2}

step 3

Find the area of the base of the rectangular prism

B=(6)(6)=36\ cm^{2}

step 4

Find the surface area

84\ cm^{2}+144\ cm^{2}+36\ cm^{2}=264\ cm^{2}

3 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?
ziro4ka [17]
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right
5 0
3 years ago
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