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kkurt [141]
2 years ago
13

In how many ways may one A, three B’s, two C’s, and one F be distributed among seven

Mathematics
1 answer:
astraxan [27]2 years ago
5 0
7 different ways is the answer
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Solve the triangle. Round your answers to the nearest tenth. Law of sines 6 A. M∠C=34 m ∠ C = 34 , b=25 b = 25 , c=16 c = 16 B.
PolarNik [594]

Answer:

A  = 43.0^o

B = 55.0^o

BC = 20.0

Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

\angle C =82^o

AB = 29

AC = 24

Required

Solve the triangle

First, we calculate \angle B using sine law:

\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}

This gives:

\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}

\frac{24}{\sin(B)} = \frac{29}{0.9903}

Cross multiply

\sin(B) * 29 = 24 * 0.9903

\sin(B) * 29 = 23.7672

Divide both sides by 29

\sin(B) = 0.8196

Take arcsin of both sides

B = \sin^{-1}(0.8196)

B = 55.0^o

Next, calculate \angle A using:

A + B + C = 180^o --- angles in a triangle

A + 55^o + 82^o = 180^o

Collect like terms

A  = 180^o-55.0^o - 82^o

A  = 43.0^o

Next, calculate BC using sine laws

\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}

This gives:

\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}

\frac{BC}{0.6820} = \frac{29}{0.9903}

Make BC the subject

BC = \frac{29*0.6820}{0.9903}

BC = 20.0

6 0
3 years ago
One number is 3 less than another number if their sum is 49
Musya8 [376]
One number is 26 the other is 23


x+y=49

Y=x+3,X (now substitute it in the equation)

x+3+x=49

2x+3=49

2x=46. X=23


Y=x+3. Y=23+3 =26 for checking 23+26=49
6 0
2 years ago
Both the football and volleyball teams have games today. The football team plays every 7 days. The volleyball team plays every 3
Allisa [31]
They will have games on the same day in 21 days
6 0
3 years ago
Simplify: (3x2 - 4x + 6) + (7x - 2)
V125BC [204]

Answer:

11x-2

Step-by-step explanation:

(3x2 - 4x + 6) + (7x - 2) This is the breakdown. (6 4x + 6)= 4x. + (7x-2) = 11x-2

8 0
3 years ago
Helppppppp pleasssseeeeee
Svet_ta [14]
14mi-5\frac{7}{10}mi=[(14-5)-\frac{7}{10}]mi=(9-\frac{7}{10})mi=(8+1-\frac{7}{10})mi\\\\=(8+\frac{10}{10}-\frac{7}{10})mi=(8+\frac{10-7}{10})mi=(8+\frac{3}{10})mi=\boxed{8\frac{3}{10}mi}\\\\other\ method\\\\14mi-5\frac{7}{10}mi=14mi-5.7mi=(14-5-0.7)mi\\\\=(9-0.7)mi=\boxed{8.3mi}
6 0
3 years ago
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