Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
I don’t see it, tell me the equation so I can do it!
Answer:
we need to see the other page or we cant solve it
Step-by-step explanation:
Answer:
$16
Step-by-step explanation:
she has $14 now
her parents let her earn 6
so $14 - $6 = $8
so thats what was left over from her allowance. she spent half of her allowance to get to $8 so you double the money
$8 * 2 = $16
$16 is her weekly allowance
Answer:
the answer is no
Step-by-step explanation:
It only shows that one pair of lines are parallel but not both are. Parallelograms have two pairs of parallel lines.