Unit 4: Linear Equations

: Sam is 12 years older than John. For the last four years, Sam and John have been friends. Five years ago, Sam was 5 times as o

Firlakuza [10]

Answer:

The present age of Sam is 20 years .

Step-by-step explanation:

Given as :

Let The age of John = J years

Let The age of Sam = S years

∵ Sam is 12 years older than John

so, The age of Sam = 12 + The age of John

i.e S = 12 + J .....1

<u>Again</u>

Before 5 years ago

The age of Sam = 5 times age of John

So, (S - 5) = 5 × (J - 5)

Or, S - 5 = 5 J - 25

Or, 5 J - S = 25 - 5

Or, 5 J - S = 20 .........2

Solving eq 1 and eq 2

[5 J - (12 + J)] = 20

Or, 5 J - 12 - J = 20

Or, 4 J = 20 + 12

Or, 4 J = 32

∴ J = $\frac{32}{4}$

i.e J = 8 years

So, The age of John = J = 8 years

Put The value of J into eq 1

∵ S = 12 + J

So, S = 12 + 8

i.e S = 20 years

So, The present age of Sam = S = 20 years .

Hence, The present age of Sam is 20 years . Answer

7 0

3 years ago

Read 2 more answers

Can help me understand this?

Tanzania [10]

Answer:

Its easy just fill in the blacks

Step-by-step explanation:

P1 is 5 P2 is 2 P3 is 4 and so on now the odd and even u add the odd number together and the even together like 2+2+1 (the even side) =5 so put 5 in the even and do the same thing to odd 5+4+6 = 15 and put 15 on odd #

Hope this helps!

4 0

3 years ago

For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = $\sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}$

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

$cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }$

3 0

2 years ago

Division of two quantities is expressed as the ____ of those two quantities.

andreev551 [17]

Division of two quantities is expressed as the quotient of those two quantities.

The word quotient is derived from the Latin language. It is from the Latin word "quotiens" which means "how many times." A quotient is the answer to a divisional problem. A divisional problem describes how many times a number will go into another. The first time that this word was known to have been used in mathematics was around 1400 - 1500 AD in England.

There are two different ways to find the quotient of two numbers. One of them is through Fractions. The quotient of a fraction is the number obtained when the fraction is simplified. The other way to find a quotient is by employing the long division method where the quotient value is positioned above the divisor and dividend.

6 0

3 years ago

What is the number nearest to 10000 which is exactly divisible by 3, 4, 5, 6, 7, and 8?.

Tems11 [23]

10080 is the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8.

Divisibility is being able to divide a number evenly and result to a whole number. Divisibility rules are set of rules to test if one number is divisible by another without doing much computation.

#1: divisibility by 2

A number is divisible by 2 if its last digit is even.

# 2: divisibility by 3:

A number is divisible by 3 if the sum of its digits is divisible by 3.

# 3: divisibility by 4

A number is divisible by 4 if the number represented by its last two digits is divisible by 4.

#4: divisibility by 5

A number is divisible by 5 if its last digit is 0 or 5.

# 5: divisibility by 6

A number is divisible by 6 if it is divisible by both 2 and 3.

# 6: divisibility by 7

Double the last digit and subtract it from a number made by the other digits. The result must be divisible by 7.

#7: divisibility by 8

A number is divisible by 8 if the number represented by its last three digits is divisible by 8.

#8: divisibility by 9

A number is divisible by 9 if the sum of its digits is divisible by 9.

# 9: divisibility by 10

A number is divisible by 10 if its last digit or the digit in the ones place is 0.

To get the number nearest to 10000 that is divisible by 3, 4, 5, 6, 7, and 8, consider first the numbers that are divisible by 5(numbers ending in 5 or 0) and narrow it down to numbers ending in 0 since numbers ending in 5 is not divisible by 2, thus making it indivisible by 6.

The process goes on by narrowing the list by checking its divisibility by 3, 4, 7 and 8.

To know more about divisibility rules, visit brainly.com/question/9462805.

#SPJ4

7 0

1 year ago