Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
(х-4)(х-6)
Step-by-step explanation:
х¹= 4
х²=6
easy
X = 59, y = 44
2x + 18 + x - 15 = 180
3x + 3 = 180
3x = 177
x = 59
x - 15 = y
59 - 15 = y
44 = y
Answer:
7/8 yards
Step-by-step explanation:
1 1/4- 3/8
first change 1 1/4 to an improper fraction: 5/4
next, find common denominator which is 8
5/4=10/8
10/8-3/8=7/8
