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7 months ago

Find the sum of the infinite geometric sequence that begins 1/12, 1/18, 1/27, …

Mathematics

1 answer:

Agata [3.3K]7 months ago

7 0

Answer:

1/4

Step-by-step explanation:

The sum of an infinite geometric series is given by the formula ...

S = a/(1 -r)

where 'a' is the first term, and r is the common ratio.

<h3>Application</h3>

Here, the first term is 1/12, and the common ratio is ...

(1/18)/(1/12) = 12/18 = 2/3

Then the sum is ...

S = (1/12)/(1 -2/3) = (1/12)/(1/3) = 3/12 = 1/4

The sum of the infinite series is 1/4.

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Solve the following equation <br><br>6x-1=3 (2x+4)-1

DIA [1.3K]

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Distribute
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Combine like terms
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3 years ago

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IceJOKER [234]

Answer:

$a_n=-12-4(n-1)$

Step-by-step explanation:

The given sequence is

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The first term of this sequence is $a_1=-12$ .

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The nth term of this arithmetic sequence is;

$a_n=a_1+d(n-1)$

We substitute the values for the first term and the common difference to obtain;

$a_n=-12-4(n-1)$

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Step-by-step explanation:

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2 years ago

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What is the slope of the line that passes through the points (-2, -1) and (2, -3)?

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Answer:

$m=\frac{-1}{2}$

Step-by-step explanation:

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Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>:

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