Answer:
![\large\boxed{-c^2(3c-2)=-3c^3+2c^2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B-c%5E2%283c-2%29%3D-3c%5E3%2B2c%5E2%7D)
Step-by-step explanation:
![-c^2(3c-2)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-c^2)(3c)+(-c^2)(-2)\\\\=-3c^3+2c^2](https://tex.z-dn.net/?f=-c%5E2%283c-2%29%5Cqquad%5Ctext%7Buse%20the%20distributive%20property%7D%5C%20a%28b%2Bc%29%3Dab%2Bac%5C%5C%5C%5C%3D%28-c%5E2%29%283c%29%2B%28-c%5E2%29%28-2%29%5C%5C%5C%5C%3D-3c%5E3%2B2c%5E2)
Answer:
![y = x+12](https://tex.z-dn.net/?f=y%20%3D%20x%2B12)
Step-by-step explanation:
Parallel => <u><em>This means it has the same slope as this one.</em></u>
Slope = m = 1
Now,
Point = (x,y) = (-6,2)
So, x = -6, y = 2
<u><em>Putting this in slope intercept form to get b</em></u>
![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
=> 2 = (1)(-6) + b
=> b = 2+6
=> b = 8
<u><em>Now putting m and b in the slope-intercept form to get the required equation:</em></u>
=> ![y = mx+b](https://tex.z-dn.net/?f=y%20%3D%20mx%2Bb)
=> ![y = x+12](https://tex.z-dn.net/?f=y%20%3D%20x%2B12)
Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
Subtract the 18 from the 78 then multiply both sides by -1, then divide by 5.