Ask question

Ask question

All categories

3 years ago

14

Alex is selling tickets to a school play. An adult ticket costs $6.50 and a student ticket costs $4.00. Alex sells x adult ticke

ts and 12 student tickets. Write a function, f(x), to represent how much money Alex collected from selling tickets

1 answer:

Tamiku [17]3 years ago

3 0

F(X)=(4)12+x6.50
f(x)=48x+6.50

You might be interested in

$1111 at 11% for 11 years

maksim [4K]

Answer:

$1344.31

Step-by-step explanation:

1111*0.11*11=1344.31

4 0

3 years ago

Suppose a subset of eight different days of the year is selected at random. What is the probability that each day is from a diff

goldfiish [28.3K]

Answer:

P = 0.05

Step-by-step explanation:

12 months * 30 days each = 360 days

From 306 days, we have to select 8 days = 360C8 ways(Total ways)

We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways

---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]

Therefore P = Number of ways of selecting each days from different month / Total number of ways

P = 12C8 * 30^8 / 360C8

P = 495 * 656100000000 / 6469697679132645

P = 0.0501985588982791

P = 0.05

Hence the probability that each day is from a different month is 0.05

6 0

3 years ago

(: (: (: (: (: (: (: (: (: (: (: (: (:

sammy [17]

Answer:

3

Step-by-step explanation:

I can see it in the demonstration graph

8 0

3 years ago

Read 2 more answers

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

3 years ago

Find the axis of symmetry for f(x)=-3x^2+5x-6

Andreyy89

Answer:

x= -5/6

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers