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jekas [21]
3 years ago
10

Mengapakah wanita hamil memerlukan jumlah nutrien yang lebih banyak berbanding wanita tidak hamil.

Computers and Technology
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

Because of the baby in the womb

Explanation:

Remember, a pregnant woman carries a life (the fetus) in her womb, and the unborn child depends on its mother for food. Such a complex and fascinating stage of pregnancy requires the mother to be well-nourished or else the child may die or suffer some health problems; which may even affect the mother.

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Maurinko [17]

Answer:

maybe a computer would be helpful

6 0
3 years ago
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Select the correct answer.
ss7ja [257]
The answer a identifying portfolio goal
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Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0
3 years ago
Differentiate among a color display, gray scale display, and a black-and-white display​
kotykmax [81]

<u>Answer:</u>

<em>Black and white</em>:

It has only two values namely black or white. The white colour in the image will be represented as “white” and other colour part will be displayed as black.

<em>Grey-scale: </em>

Again the white part does not have a change, the black and other coloured items will be displayed in grey.

<em>Coloured image: </em>

It would display the actual colour of the image. The number of colours and shades depends on the original image from where actually it has been shooted and it also depends on the quality of the camera.

4 0
3 years ago
Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera
zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

}

8 0
2 years ago
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