Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Most likely B. Photographs.
Hope this helps!
Have a good day!
Answer: it does – or perhaps appears to do – in the world.
Explanation:
sorry if am not right have a nice day lol
Answer:
Explanation:
As a user of GPL v3 software, you have lots of freedom: You can use GPL software for commercial purposes. You can modify the software and create derivative work. You can distribute the software and any derivative work you produce, without having to ask for permission or pay
The packet is
dropped or discarded. By default, a router will send packets
to a network that has been listed in the routing table. If it happens that the
network is not listed, the packet will be discarded or dropped. Packets that do
not have a default route or gateway of last resort are dropped.
