Ask question

Ask question

All categories

3 years ago

6

(6+7) +5 =6+(3+5) true or false

2 answers:

mojhsa [17]3 years ago

6 0

Answer:false

Step-by-step explanation:(6+7) +5 is 18 but 6+(3+5) is 14

Rus_ich [418]3 years ago

3 0

Answer:

False

Step-by-step explanation:

13+5=6+8

18=14

false

You might be interested in

PLEASE ANSWER ASAP the quiz is almost over and I need to turn this in

andriy [413]

Answer:

X = 10

Step-by-step explanation:

the triangles are similar meaning one is smaller we have all the sides on the smaller one

10 to 25 is a 2.5 increase

so 4 x 2.5 = 10

5 0

2 years ago

Read 2 more answers

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

<u>Step1:</u>-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

<u>Step 2</u>:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

<u>Step 3</u>:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

3 years ago

The perimeter of a rectangle is 182 ft. The width is two more feet than the length . Find the length and width.

Kamila [148]

Let's call the width $w$ and the length $l$ based on this, we can make two equations based on the first and second sentences in the problem.

$w = l + 2$

$2l + 2w = 182$

If we substitute $l + 2$ for $w$ into the second equation, we can make the following:

$2l + 2(l + 2) = 182$

Substitute

$2l + 2l + 4 = 182$

Use the Distributive Property

$4l + 4 = 182$

Combine like terms

$4l = 178$

Subtract 4 from both sides

$l = \dfrac{178}{4} = \dfrac{89}{2}$

Divide both sides by 4 and simplify

Now, let's find $w$ :

$w = l + 2 = \dfrac{89}{2} + 2 = \dfrac{93}{2}$

The length of the rectangle is $\boxed{\dfrac{89}{2} \,\textrm{ft}}$ and the width of the rectangle is $\boxed{\dfrac{93}{2} \,\textrm{ft}}$ .

5 0

3 years ago

Jordan said 60% of 150 people is 80 people.Is his answer correct?Explain why or why not.

jek_recluse [69]

150 times .6 is 90 not 80 that is why Jordan is incorrect

6 0

3 years ago

Read 2 more answers

describe the steps you used to solve the equation and find the amount of carries allowance. linear equation: 1/4a+1/3a+8=22

vlabodo [156]

1/4a + 1/3a +8 =22

1st step add like terms:

1/4a +1/3a = 3/12a +4/12a = 7/12a

7/12a +8 =22

2nd step subtract 8 from each side:

7/12a = 14

3rd step divide both sides by 7/12 to get a:

a = 14 / 7/12

a = 24

7 0

3 years ago

Read 2 more answers