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2 years ago

At 7:00 a.m., the temperature was -3°F. At 6:00 p.m., the temperature was

Mathematics

1 answer:

san4es73 [151]2 years ago

4 0

Answer:

A) -3 + 9 + 4

Step-by-step explanation:

We are given the following information: At 7:00 a.m., the temperature was -3°F. At 6:00 p.m., the temperature was 9°F greater than the temperature at 7:00 a.m. This means the temperature at 6:00 p.m. is calculated as -3 + 9.

We know this last temperature is 4°F less than the temperature at noon, thus the temperature at noon is calculated as -3 + 9 + 4

A) -3 + 9 + 4

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Answer:

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Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

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$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

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$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

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expand to remove the bracket

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