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SOVA2 [1]
2 years ago
13

Write an equation in slope-intercept form for the line parallel to y = 5x - 2 that passes through the point (8, -2).

Mathematics
1 answer:
steposvetlana [31]2 years ago
6 0

Answer:

$ y = 5x - 42 $

Step-by-step explanation:

The equation of parallel line differ only by their constant.

Hence, the equation of the line parallel to $ y = 5x - 2 $ is nothing but $ y = 5x + c $

When a point passing through this line is given we can substitute the point in this line and get the value for $ c $.

The line passes through $ (8 , -2) $.

Therefore, we have: $ -2 = 5(8) + c $

$ \implies c = -42$.

Substituting this we get the equation of the parallel line as $ y = 5x - 42 $.

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Answer:

45 sq.units

Step-by-step explanation:

to get area of a triangle, it would be base*height/2, so 15*6/2 would be 90/2, which ends up being 45, which is the answer.

4 0
1 year ago
Help please thank you.
Shkiper50 [21]
3 \sqrt{5} + 6 \sqrt{9} \sqrt{5}
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3 years ago
Which of the following describes the end behavior of<br> f(x) = (1/2)^x
NARA [144]

Answer:

as x approaches infinity, f(x) approaches 0

as x approaches -infinity, f(x) approaches infinity

Step-by-step explanation:

we can observe that 1/2 < 1 and since it's being exponentiated, the f(x) gets smaller and smaller as x gets bigger.

For example, f(0) = 1, f(1) = 1/2, f(2) = 1/4

so, as x approaches an infinitely large number, f(x) gets closer and closer to zero.

this is the opposite as x approaches a negatively large number. following exponential rules, 1/2^(x) = 2^x for all x < 0. therefore as x approaches negative infinity, f(x) approaches infinity.

in this case, f(-1) = 2, f(2) = 4, f(3) = 8

4 0
2 years ago
If Sheila drove 152 km at an average speed of 95 km/h, how much time did her trip take?
sattari [20]

1.6 hours

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6 0
3 years ago
Read 2 more answers
A rectangular prism has a height of 12 cm and a square base with sides measuring 5 cm. A pyramid with the same base and the heig
Ksju [112]
The answer is 200 cm³


The volume of the rectangular prism (V1) is:
V1 = l · w · h                       (l - length,  w - width,  h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
Thus: V1 = 12 · 5 · 5 = 300 cm³

The volume of pyramid (V2) is:
V2 = 1/3 · l · w · h                   (l - length,  w - width,  h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
V2 = 1/3 · 12 · 5 · 5 = 1/3 · 300 = 100 cm³


The volume of the space outside the pyramid but inside the prism (V) is a difference between the volume of the rectangular prism (V1) and the volume of the pyramid (V2): 
V = V1 - V2 = 300 cm³ - 100 cm³ = 200 cm³
3 0
2 years ago
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