4 years ago

Volume

1 answer:

3 0

Formula =

$\frac{4}{3}* \pi r^3

$

Plug 9 for r

Multiply 4/3 * 9^2 = 972

Leave pi as is

972 $\pi$ is the answer

You might be interested in

ddd [48]

There are

$\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}$

ways of pairing up any 2 members from the pool of $2n$ contestants. Note that

$(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)$

so that

$\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}$

4 0

2 years ago

a_sh-v [17]

Step-by-step explanation:

HCF of 60 and 84 = 6

So the required greatest number that divides 60 and 84 without leaving remainder is 6.

6 0

3 years ago

NeTakaya

Dollars is the dependent quantity because the amount you pay depends on how many gallons you've pumped.

6 0

4 years ago

tigry1 [53]

Answer:

18m

Step-by-step explanation:

113.04m/3.14 = 36m/4m = 9m*2 = 18m

7 0

3 years ago

melamori03 [73]

Answer:

250 MAYBE

Step-by-step explanation:

3 0

3 years ago