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stepladder [879]
3 years ago
14

The total weight of the golf balls from Julio’s golf bag was 273 grams. If each golf ball weighed 45.5 grams, which graph shows

the weight of golf balls as it relates to the number of golf balls?
Weight of Golf Balls
Number of Golf Balls
Weight (in grams)
1
45.5
2
?
3
?
?
273

On a coordinate plane, the x-axis is labeled number of golf balls and the y-axis is labeled weight (in grams). A line goes through point (1, 50) and (6, 275).

On a coordinate plane, the x-axis is labeled number of golf balls and the y-axis is labeled weight (in grams). A line goes through point (10, 50) and (50, 300).

On a coordinate plane, the x-axis is labeled number of golf balls and the y-axis is labeled weight (in grams). A line goes through point (50, 1) and (250, 5.5).

On a coordinate plane, the x-axis is labeled number of golf balls and the y-axis is labeled weight (in grams). A line goes through point (50, 9.9) and (300, 50).
Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

ANSWER:

A

EXPLAIN:

Since all the six balls have same weight and the total weight is given as 273g, then weight of one ball will be

273/6=45.5 g

1 ball=45.5 g

2 balls =2*45.5=91 g

3 balls =3*45.5=136.5 g

4 balls=4*45.5=182 g

5 balls =5*45.5=227.5 g

6 balls =6*45.5=273 g

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snow_lady [41]

First, let's check if the sequence is geometric or arithmetric.

If arithmetric, the sequence will have common difference.

<u>A</u><u>r</u><u>i</u><u>t</u><u>h</u><u>m</u><u>e</u><u>t</u><u>r</u><u>i</u><u>c</u>

\displaystyle \large{a_{n + 1} - a_n = d}

d stands for a common difference. Common Difference means that sequences must have same difference after subtracting.

<u>G</u><u>e</u><u>o</u><u>m</u><u>e</u><u>t</u><u>r</u><u>i</u><u>c</u>

\displaystyle \large{ \frac{a_{n + 1}}{a_n}  = r}

r stands for a common ratio.

To find the value of y, you can check the sequence. If we try subtracting the sequences, the differences are different. That means the sequences are not arithmetric. That only leaves the geometric sequence.

Let's check by dividing sequences.

We have:

  • 2,y,18,-54,162,...

Let's check by divide -54 by 18 and 162 by -54. We need to divide more than one so we can prove that the sequence is geometric.

\displaystyle \large{ \frac{ - 54}{18}  = - 3 } \\  \displaystyle \large{ \frac{ 162}{ - 54}  = - 3}

Hence, the sequence is geometric.

Because the common ratio is -3. Let these be the following:

\displaystyle \large{ a_{n + 1} = y } \\  \displaystyle \large{ a_n = 2 } \\  \displaystyle \large{ r =  - 3 }

From the:

\displaystyle \large{ \frac{a_{n + 1}}{a_n}  = r}

Substitute the values in.

\displaystyle \large{ \frac{y}{2}  =  - 3}

Multiply the whole equation by 2 to isolate y.

\displaystyle \large{ \frac{y}{2} \times 2  =  - 3 \times 2} \\  \displaystyle \large{ y =  - 6}

Therefore, the value of y is -6.

7 0
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Advocard [28]

Answer:

There are 35 adult dogs and 20 puppies

<em></em>

Step-by-step explanation:

<em>Represent the puppies with P and the Adult dogs with A</em>

Given

A : P = 7 : 4

Dogs = 55

Required

Determine A and P

First, we need to sum the ratios;

Total = A + P

Total = 7 + 4

Total = 11

Adult Dogs is then calculated as follows;

A = \frac{A\ Ratio}{Total} * Dogs

A = \frac{7}{11} * 55

A = \frac{385}{11}

A = 35

Puppies is calculated by subtracting the number of adult dogs from the total

P = Dogs - Adult\ Dogs

P = 55 - 35

P = 20

<em>Hence;</em>

<em>There are 35 adult dogs and 20 puppies</em>

3 0
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AnnZ [28]
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8_murik_8 [283]

Answer:

1

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Step2247 [10]
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6 0
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