Answer:
None of these options has "no solution"
Step-by-step explanation:
we will verify each options
(1)
y = 4x and y = 2x - 3
we can set them equal and solve for x
Since, solutions exists
so, this is FALSE
(2)
y = -4x and y = 2x - 3
we can set them equal and solve for x
Since, solutions exists
so, this is FALSE
(3)
y = 4x and y = 2x+ 3
we can set them equal and solve for x
Since, solutions exists
so, this is FALSE
(4)
y = -4-x and y = 2x - 3
we can set them equal and solve for x
Since, solutions exists
so, this is FALSE
So, No system of equations have no solution
Answer:
yessssss
Step-by-step explanation:
...........
Answer:
Then, a=-1 and b=-1
Step-by-step explanation:
We need to solve the following system of equations using the adition method:
2a+3b=-1 (i)
3a+5b=-2 (ii)
First, we multiply the equation (i) by -3 and the equation (ii) by 2, so we get:
-6a-9b=3
6a+10b=-4
Adding the two equations we have:
-6a-9b=3
6a+10b=-4
--------------------------
0 + b = -1
Then b=-1. Now, let's substitute the value of b into equation (i):
2a+3b=-1
2a + 3(-1) = -1
2a -3 = -1
2a = 2
a = 1
Then, a=-1 and b=-1
The correct answer is the correct spelling correct answer is that I don’t answer my question about it is correct
Answer:
A) The minimum required diameter of the brass shaft D₁ = 0.00176 m
B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m
Step-by-step explanation:
<u>Data:</u>
A compound shaft has two segments made of brass and aluminium
Allowable shear stress of Brass = 69 MPa.
allowable sheer stress of Aluminium = 86 MPa.
Torque TC = 23900 N-m
<u />
<u>Find</u>: Minimum required diameter of the brass D₁ and Auminium D₂
<u>Solution</u>: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.