The lower quartile is the value of the middle of the first set.
The upper quartile is the value of the middle of the second set.
Answer: <u>A. 35</u>
Step-by-step explanation: The largest prime number less than 50. The largest number less than 50 is 49, but it is not prime, because 49=7·7. The previous number is 48, but it is also composite, because 48=2·2·2·2·3. The previous number is 47, it is prime.
The smallest composite number greater than 10. The smallest number greater than 10 is 11, but it is prime. The next number is 12, it is composite, because 12=2·2·3.
The difference between the largest prime number less than 50 and the smallest composite number greater than 10 is<u> 47-12=35.</u>
Answer:
y=120-4x
Step-by-step explanation:
Here we are given the average speed for Day 1 and Day 2 and the time of ride . We asked to Find an expression to determine the total distance travelled in two days.
Day 1 :
Avg Speed = 8 mph
Let the time for travelling = x hrs
Hence Distace Travelled D1= Speed x Time
D1=8x
Day 2 :
Avg Speed = 12 mph
Total time of travelling for two days is given as 10 hours . Hence the time of travelling for day 2 is
= (10-x) hrs
Hence Distance travelled in Day 2 D2 = speed x time
D2 = 12(10-x)
D2=120-12x
Total Distance travelled = D1 + D2
= 8x+120-12x
=120-4x
If the total distance travelled is denoted by y
The expression will be
y=120-4x
Answer:


Step-by-step explanation:
Given

Required
Complete the model
[ ] x = 6.60
x = _ hundredths

Equate to x

Multiply both sides by 15



So, we have:
[ ] x = 6.60 =====> 
Recall that:


This implies that:

Hence:
x = _ hundredths =====> 
Using the equations y-3x=3 and x+y=31 you can find that x=7 and y=24. There for x is the smaller of the two numbers.