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zhannawk [14.2K]
3 years ago
11

The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea

n of: μ = 473 and a standard deviation of: σ = 28. According to the standard deviation rule, almost 0.15% of the students spent more than what amount of money on textbooks in a semester?
Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

Step-by-step explanation:

Given data:

\mu = 473

standard deviation is \sigma=  28

As distribution is normal in shape and values are symmetrical

The standard deviation rule says that 95% of observation lies between the second standard deviation of the mean

so, approximately only 5% of observation lies outside the interval and normal shape is symmetric. hence approximately 0.15% of observation lies above the interval

             = \mu + 2\times \sigma

             = 473 + 2\times 28 = 529

almost 0.15% of students spent more amount is 529

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OLga [1]

Answer:

x = 6

Step-by-step explanation:

54/6 is 9. This is the only correct one.

Hope it helps!

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Write a function in terms of t that represents the situation.
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Kenyl covers the front of a circular bulletin board with fabric that costs 1.48 per square foot. The bulletin board has a radius
Gnoma [55]

Answer:

29

Step-by-step explanation:

In this question we are trying to calculate the cost of exact amount of fabric used given the cost per area of the fabric.

To answer this question mathematically, we need to know the area of the bulletin board. To do this , we employ a mathematical approach. We know that the bulletin board is circular in shape from the question and thus we calculate the area of this shape.

Mathematically, the area of the circular bulletin board is pi * r^2 where r refers to the radius. From the question, we can identify that this radius is 2.5 feet. let’s insert this into the equation we have.

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The cost of the fabric per square feet is 1.48.

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3 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

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3 years ago
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Julli [10]

Answer:

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Step-by-step explanation:

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