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Blababa [14]
3 years ago
6

How do you solve radical and division to this problem

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0
15/4 = 3.75;
\sqrt{15/4} = \sqrt{15} /2 = 3.87/2 = 1.935;
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What are your guys favorite marsupials?
IgorC [24]

Answer:

koalas

Step - by - step explanation:

because they're so cute and cuddly

3 0
2 years ago
. A theater has 40 rows of seats, where the first row has 27 seats and each subsequent row has
MAXImum [283]
<h3><em>Answer:</em></h3><h3><em></em></h3><h3><em>number of seats in theater = 1035</em></h3><h3><em></em></h3><h3><em>Step-by-step explanation:</em></h3><h3><em></em></h3><h3><em>Given in question as</em></h3><h3><em></em></h3><h3><em>Total number of rows of seat = 30</em></h3><h3><em></em></h3><h3><em>first row contain seat = 20</em></h3><h3><em></em></h3><h3><em>second row contain seat = 21 .. and so on</em></h3><h3><em></em></h3><h3><em>This is in arithmetic progression as 20 , 21 , 22 , 23 ...... so on</em></h3><h3><em></em></h3><h3><em>Then as number of terms N = 30 and first terms = a = 20</em></h3><h3><em></em></h3><h3><em>so we have to find Tn th terms</em></h3><h3><em></em></h3><h3><em>So, Tn th terms = first term + ( N -1 ) × d               d= common difference i.e 1</em></h3><h3><em></em></h3><h3><em>     Tn th terms = 20 + (30 - 1) × 1</em></h3><h3><em></em></h3><h3><em>Thus, Tn th terms = 49</em></h3><h3><em></em></h3><h3><em>i.e The number of seats in 30th row = 49</em></h3><h3><em></em></h3><h3><em>Now again Total number of seats in theater</em></h3><h3><em></em></h3><h3><em>sum of Nth terms = </em></h3><h3><em></em></h3><h3><em>so                         = </em></h3><h3><em></em></h3><h3><em>                            = 15 × 69 = 1035</em></h3><h3><em></em></h3><h3><em>Hence, Total number of seats in theater = 1035      Answer</em></h3>
6 0
3 years ago
Find the rule.
mezya [45]

The <em>first</em> series uses a <em>linear</em> function with - 1 as <em>first</em> element and 1 as <em>common</em> difference, then the rule corresponding to the series is y = |- 1 + x|.

The <em>second</em> series uses a <em>linear</em> function with - 3 as <em>second</em> element as 2 as <em>common</em> difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

<h3>What is the pattern and the function behind a given series?</h3>

In this problem we have two cases of <em>arithmetic</em> series, which are sets of elements generated by a condition in the form of <em>linear</em> function and inside <em>absolute</em> power. <em>Linear</em> <em>functions</em> used in these series are of the form:

y = a + r · x      (1)

Where:

  • a - Value of the first element of the series.
  • r - Common difference between two consecutive numbers of the series.
  • x - Index of the element of the series.

The <em>first</em> series uses a <em>linear</em> function with - 1 as <em>first</em> element and 1 as <em>common</em> difference, then the rule corresponding to the series is y = |- 1 + x|.

The <em>second</em> series uses a <em>linear</em> function with - 3 as <em>second</em> element as 2 as <em>common</em> difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

To learn more on series: brainly.com/question/15415793

#SPJ1

7 0
1 year ago
If ƒ(x ) = 3x + 1 and ƒ -1 = , then ƒ -1(7) =
Elden [556K]
F(x) = 3x + 1

let f(x) = y

y = 3x + 1

y - 1 = 3x

3x = y - 1

x = (y - 1)/3

From y = f(x),  x = f⁻¹(y) 

<span>x = (y - 1)/3
</span>
 f⁻¹(y)  = (y - 1)/3

f⁻¹(7)  = <span>(7 - 1)/3 = 6/3 = 2

</span>f⁻¹(7)<span> = 2</span>
6 0
3 years ago
Write the equation in logarithmic form 4^7=16,384 please show work
nlexa [21]

 If a^ x = b then:  

x = log_{a}b  

For:

4^{7} = 16384 \\ log _{4}16384 = 7

8 0
3 years ago
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