Answer:
it's the last one.
Step-by-step explanation:
both of them have ÀF as part of their angle.
Answer:
x² + 2x + (3 / (x − 1))
Step-by-step explanation:
Start by setting up the division:
.........____________
x − 1 | x³ + x² − 2x + 3
Start with the first term, x³. Divided by x, that's x². So:
.........____x²______
x − 1 | x³ + x² − 2x + 3
Multiply x − 1 by x², subtract the result, and drop down the next term:
.........____x²______
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Repeat the process over again. First term is 2x². Divided by x is 2x. So:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Multiply, subtract the result, and drop down the next term:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
.................-(2x² − 2x)
.................---------------
.....................................3
x doesn't divide into 3, so that's the remainder.
Therefore, the answer is:
x² + 2x + (3 / (x − 1))
∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
brainly.com/question/25882965
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