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xxMikexx [17]
3 years ago
9

Which rectangle could be created from a parallelogram with a base of 6 and a height of 2?

Mathematics
1 answer:
nalin [4]3 years ago
5 0

Answer:

A rectangle with a length of 6 and width of 2.

The corners added up make a rectangle so it is the same as a rectangle. You can just multiply 6 x 2 = 12 to find the area. If you have any more questions you are welcome to ask

Step-by-step explanation:

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(3 * 2)2/6 - 5 + (4 - 1)2?
saul85 [17]

Answer: The answer is 3.

7 0
2 years ago
Read 2 more answers
8 times the difference between a number and 6 is equal to 4 times the number.
7nadin3 [17]

Answer:

The variable titled "the number" is A: 12.

Step-by-step explanation:

The problem is 8 * (x - 6) = 4 * x

Try the first number as x and rewrite the expression.

8 * (12 - 6) = 4 * 12

Following PEMDAS (the Order of Operations), you need to solve the problem inside the parenthesis.

12 - 6 = 6

Rewrite the problem.

8 * 6 = 4 * 12

8 times 6 is 48.

4 times 12 is 48.

The variable in the expression 8 * (x - 6) = 4 * x is 12.

4 0
2 years ago
1) 2(a + 3) = -12
serg [7]
1)
2(a + 3) = -12
Divide by 2
a + 3 = -6
Subtract 3
a = -9

2)
3(p + 2) = 18
Divide by 3
p + 2 = 6
Subtract 2
p = 4

3)
4(2r + 8) = 88
Dive by 4
2r + 8 = 22
Subtract 8
2r = 14
Divide by 2
r = 7

4)
2(3a + 2) = -8
Divide by 2
3a + 2 = -4
Subtract 2
3a = -6
Divide by 3
a = -2

5)
4(k + 3) = 4
Divide by 4
k + 3 = 1
Subtract 3
k = -2
3 0
3 years ago
Read 2 more answers
Help me please I don't get it​
julsineya [31]

Answer:

it's the last one

Step-by-step explanation:

to find the perimeter, you must add all the sides.

25 plus 25 is 50

multiple x by two for both sides and that will give you the perimeter of 70

6 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
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