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laila [671]
3 years ago
13

(look at image) can i get help on this?

Mathematics
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

1. angle 5 and angle 6 are not liner pair

2.yes angle 5 and 9 r linear pair.

3.no angle 5 and angle 8 are not linear pair

4.yes angle 5 and 8 are vertical angles

5.no angle 5 and angle 7 are not vertical angles.

6.no angle 9 and angle 6 are not vertical angles.

<em><u>please mark it as brainliest!!</u></em>

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Please help me with this question
Sergio039 [100]

Isn't that simply asking you to compute 30% of 20?

30              x

-----   =    ------

100           20


100x = 600

      x = 6


So, out of those 20 numbers, you would expect that 6 of them would begin with the digit 1.

7 0
2 years ago
N= A-b <br> solve for A <br> hurry plzzzzz
Scrat [10]

Answer:

A=B+n

Step-by-step explanation:

plz mark me as brainliest

4 0
2 years ago
Read 2 more answers
If
KengaRu [80]

Answer:

2112

Step-by-step explanation:

4752÷36= 132

132×16=2112

5 0
3 years ago
What is the product of the rational expressions below
ankoles [38]
The answer to the question is a
8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali
Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}

rewrite the root

\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}

then cancel the terms that are cubes and bring them out of the root

\sqrt[3]{80}=2\sqrt[3]{10}

7 0
1 year ago
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