Answer:
When x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ +∞
Step-by-step explanation:
Hi there!
First, let´s write the function:
f(x) = (7x⁵ - 3x +1) / (4x³ + 2)
When x ⇒ +∞
f(x) ⇒ (7x⁵ - 3x) / 4x³ because (7x⁵ - 3x)>>>1 and 4x³>>>2 we can neglect those constants.
f(x) ⇒7x⁵/4x³ - 3x/4x³
f(x) ⇒ 1.75x² - 0.75/x² (0.75/x² ⇒ 0 because a number divided by a very big number is approximately zero). Then:
f(x) ⇒ 1.75x² ⇒ +∞
When x ⇒ -∞
f(x) ⇒ 1.75x² = +∞ (because x² is always positive)
Then, when x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ +∞
Answer:
-22, -6, 4, 9, 19
Step-by-step explanation:
hope this helps
Solve:
3x^2 - 5x + 7 = 0
Answer : x = 5/6 + i sqrt 59/6, x = 5/6 + i sqrt 59/6
Solve the Equation:
3x^2 - 5x + 7 = 0
Step 1: Use quadratic Formula with a = 3, b = -5, c = 7:
x = -b +/- sqrt b^2 - 4ac/ 2a
x = - ( - 5) +/- sqrt ( - 5)^2 - 4(3)(7)/ 2(3)
x = 5 +/- sqrt - 59/6, which will become, x = 5 +/- sqrt i 59/6, x = 5 +/- sqrt i 59/6
No Real Solutions:
Your answer would be, Letter Choice, (D), x equals the quantity of plus, or minus i sqrt 59 all over 6. Hence, No Real Solutions
Hope that helps!!!! : )
Magnitude is sqrt ( -sqrt2/2 ^2 + -sqrt2/2 ^2)
= sqrt (0.5 + 0.5)
= 1
The vector is in the third quadrant and its tangent = 1 so the angle is 180 + 45
= 225 degrees
Use the site cymath it helps a lot but X<0, X>1/8