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miv72 [106K]
3 years ago
6

Solve the equation using any technique 6x^2-5x-1=0

Mathematics
2 answers:
liberstina [14]3 years ago
8 0
(6x+1)(x-1)
x= -1/6, 1
D
zheka24 [161]3 years ago
7 0

Answer:

D)x=-1/6;x=1

Step-by-step explanation:


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Michael has a total of$4.40 in dimes (1 dime=$0.10) and quarters (1quarter=$0.25), and he has 20 coins in total. Which of the fo
Vesnalui [34]
A) d+q=20
0.1d+0.25q=4.40 Let's just read what this says: first, # of dimes (d) plus # of quarters (q) is 20.The second equation can be called the VALUE EQUATION; it says that one tenth of a dollar ($0.10) times the # of dimes is part of the total monetary value, and that one quarter of a dollar ($0.25) times the # of 'quarter' coins is the other part of this stash, and it totals $4.40. VOTE FOR A.
5 0
3 years ago
Bob is doing a quality test on machine bots , he tested 24 bolts that he randomly found that 5 were defective. Based on bob’s re
goldenfox [79]

Answer:

175

Step-by-step explanation:

5/24 = 0.208 percentage of defective bolts

scale up to 840 bolts by finding 20.8% of defective bolts

840*20.8 = 175

5 0
2 years ago
Please help asap! Add using the number line.
sweet-ann [11.9K]

Answer:

0.6

Step-by-step explanation:

1) 1.4-0.8 (A negative and a positive equals a negative, then you just subtract. On the number line you would start at 1.4 and go back)

hope this helps!

6 0
3 years ago
Please help me first answer gets brainliest please dont play around
Crazy boy [7]

Answer:

8b- 13 6/7

Step-by-step explanation:

A product of 8 and b just means 8 x b or 8b.

13 6/7 less than that product means subtraction.

Therefore, it would be 8b - 13\frac{6}{7}

6 0
3 years ago
Read 2 more answers
You want to put a fence around your field. The cost of fencing is $60 per meter. The
Darina [25.2K]
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000

Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000

Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000


3 0
2 years ago
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