In a ring species gene flow occurs between neighboring populations of a species, but at the end of the ring populations don’t interbreed.
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Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.
C- has a heterozygous genotype
They are genotypes (represents genes)
I think it is a plant cell model
