9514 1404 393
Answer:
32°, 58°
Step-by-step explanation:
The second angle is (3x-38), and their sum is ...
x +(3x -38) = 90
4x = 128 . . . . . . . . . add 38 and simplify
x = 32 . . . . . first angle
3x -38 = 3·32 -38 = 58 . . . . . . second angle
The measures of the two angles are 32° and 58°.
Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²
I think the best answer would be 2)
To answer we let x be the distance he covered in the first part of the trip and y be the distance in the second part of the trip. The time it took him to finish the first trip is x/8 and the second y/20. The equations that best represent the given scenario is,
x + y = 15
x/8 + y/20 = 1.125
The values of x and y are 5 and 10, respectively.