Answer:
Step-by-step explanation:
When we consider Area under arc AC is is representing a quarter as ADBC is a square,
.
Area of quadrant = 
here r= 8 cm
Area under Arc AC= 
Area of white region ABC = Area of square ADBC - Area under Arc AC
![=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2](https://tex.z-dn.net/?f=%3D8%5E2-16%5Cpi%5C%20%5C%20%20%20%20%20%5B%5Ctext%7BArea%20of%20square%7D%20%3D%20sides%5E2%5D%5C%5C%5C%5C%3D%2064-16%5Cpi%5C%20%5C%20%20%3D16%284-%5Cpi%29%5C%20cm%5E2)
Similarly , Area of white region ADC = 
Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

Area of shaded region =
Length of arc AC = 

Perimeter of shaded region = 2(AC) = 
Answer:
Step-by-step explanation:
I would have thought the answer would be whole numbers...
using top line....
5x-5y + 7x-15 = 180 (that is a line)
12x - 5y = 195
using bottom line
4x+ 4y +2x+ y = 180
6x + 5y =180
~~~~~~~~~~~~~~~~~~
12x - 5y = 195
6x + 5y =180
(fives cancel)
18x = 375
x = 20.83
y= 11
The slope is

and the y intercept is -1
so the equation is y =

x-1
Answer:The coordinates of point P are -8, -4.
Step-by-step explanation:
Answer:

Step-by-step explanation:

