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vichka [17]
3 years ago
15

A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. inside the container there is empty space not

taken up by the volleyball. what is the volume of that empty space? use 3.14 for ? and round the answer to the nearest cubic inch.
Mathematics
2 answers:
salantis [7]3 years ago
5 0
4599^3 (choice b) is correct
asambeis [7]3 years ago
4 0

Volume of Sphere is V=(4/3)*PI*r^3

The radius of the volleyball is 13 inches

<span>So V=(4/3) * 3.14 * 13^3 =  9198 cubic inches</span>

 

Volume of a cylinder is V=pi * r^2 *h

Since they say the ball fits perfectly

The radius is 13 and the height is 26 ( the diameter of the ball)

So V=3.14 * 13^2 * 26 = 13,797 cubic inches

 

13797 – 9198 = 4,599 cubic inches of empty space


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<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

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The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

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The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

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