Answer:
Rate of change for the linear relationship modeled is 
Step-by-step explanation:
As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.
We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,
Putting the points as (-1, 10) and (1, 9), we get
Rate of change is the slope of the line joining all these points.
40/1 is the same 80/2 120/3 160/4
The slope is m = rise/run
m = ( -3 - 6 ) / ( 5 - ( -2 )) = -9 / ( 5 + 2 ) = - 9/7
Answer: the slope of the line is -9/7.
Since the plane descends 1,300 feet per minute it would descend 19,500 feet after 15 minutes (1,300 x 15 = 19,500) Subtract this from the plane's initial altitude 32,000 and the new altitude will be 12,500. (32,000-19,500=12,500)
1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.
6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)
