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love history [14]
3 years ago
14

(8y-4) -2(1/4y+3) so I'm doing add & subtract expressions and really need the help

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

7 1/2y +2

Step-by-step explanation:

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The picture below shows a box sliding down a ramp:
algol [13]

Answer:

11.3 ft

Step-by-step explanation:

sin = opp/hyp

hyp = opp/sin

AC = 10/sin62

Use calculator

AC = 11.325700506890392

11.3 ft

8 0
3 years ago
At a putt putt course there are 50 yellow golf balls, 45 red golf balls, and 65 blue golf balls. What ratio compares the number
oksian1 [2.3K]
Blue balls : Total number.

Total number of balls = 50 + 45 + 65 = 160

Blue balls : Total number.

= 65: 160    Divide both by 5.
= 13 : 32

= 13/32.    That is the ratio.

6 0
3 years ago
Find the value of x in the triangle... Then classify the triangle as acute, right or obtuse
ddd [48]

Answer:

x = 44

right

Step-by-step explanation:

The sum of the angles in a triangle add to 180

90+ 46+x = 180

Combine like terms

136+x = 180

Subtract 136 from each side

136+x-136=180-136

x =44

Since we have a 90 degree angle it is a right triangle

4 0
3 years ago
The equation c=6.4w represents the cost c for w pounds of walnuts.Does a value of 2.5 for w make sense.
Nikolay [14]

Answer:

c=16

Step-by-step explanation:

c=6.4*2.5=16

4 0
3 years ago
Describe the shaded areas.​
melomori [17]

9514 1404 393

Answer:

  the difference of 2 or 3 rectangles

Step-by-step explanation:

In every case, the "shaded" area can be computed by finding the area of a "bounding" rectangle, and subtracting the areas of the rectangular cutouts that give the figure its shape.

(a) The cutout is the white space at upper right. (Insufficient dimensions are given.)

(b) The cutout is the white space at lower left. The bounding rectangle is 8×7, and the cutout is 4×3.

(c) The cutout is the rectangle in the middle. The bounding rectangle is 13×7, and the cutout is 4×1.

(d) The cutouts are the rectangles on either side. They could be considered as a single unit. The bounding rectangle is 20×25; the cutouts have a total width of 16 and a height of 20, so total 16×20.

(e) Similar to (d), the cutouts are the white spaces on either side. The bounding rectangle is 14×12. The cutouts total 12 in width and 3 in height, so total 12×3.

__

You will note in (d) and (e) that the dimensions of the cutouts have something in common with the dimensions of the bounding rectangle. This means the problem can be simplified a little bit by factoring out that common factor. In (e), for example, 14×12 -(12×3) = 12(14 -3) = 12×11

4 0
3 years ago
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