All categories

3 years ago

(8y-4) -2(1/4y+3) so I'm doing add & subtract expressions and really need the help

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

Answer:

7 1/2y +2

Step-by-step explanation:

You might be interested in

A t shirt says it cost $14 when you get up to the counter she tells you everything is stories 20% off how much was the discount

cestrela7 [59]

It is $2.80 off the t-shirt which would make the new price $11.20

8 0

3 years ago

Records show that 12% of all college students are foreign students who also smoke. It is also known that 40% of all foreign coll

Sati [7]

Answer: the percent of the students at this university are foreign = 30%

Step-by-step explanation:

Given: Probability that college students are foreign students who also smoke: P(S|F)=0.12

Probability that foreign college students smoke P(S∩F)=0.4

The probability that the students at this university are foreign :

$P(F)=\dfrac{P(S\cap F)}{P(S|F)}$ [By conditional probability formula]

$=\dfrac{0.12}{0.4}\\\\=0.3$

Hence, the percent of the students at this university are foreign = 30%

6 0

3 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

3 0

3 years ago

Will mark BRAINLIESTT

bogdanovich [222]

Answer:

2.5

Step-by-step explanation:

16-13.50

6 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

3 years ago