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klio [65]
3 years ago
7

I need help with math!!! time is running out!!! will mark brainliest!!!

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0
1.

Answer A. (x<1)

2.

Answer A.

3.

Answer A. (x<0)

4.

Answer D. (x>2.5)
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Factors of polynomial 3xsquare +x-4
Dennis_Churaev [7]

Answer:

(3x + 4)(x - 1)

Step-by-step explanation:

3x^2 + x - 4

use middle term break method

we need two number which gives 12 when multiplied and 1 when subtracted

3x^2 + (4 - 3)x - 4

3x^2 + 4x - 3x - 4

x(3x + 4) -1(3x + 4)

(3x + 4)(x - 1)

4 0
2 years ago
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Please Help Me , This Is My Last Question I WILL REWARD BRAINLIEST !
WARRIOR [948]
What is that supposed to mean
3 0
3 years ago
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Two weeks ago Audrey earned 84$ for 7 hours of work this week she earned 132$ for 11 hours of work find the numerical value of t
natima [27]
The slope of the line is 12
3 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se
sertanlavr [38]

Answer:

The volume of the solid is: \mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}

Step-by-step explanation:

GIven that :

y = 2 + sec \  x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \  y \ = 2

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid  can be calculated as follows:

V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx

V = \pi [4x - tan \  x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}}  \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})]  \\ \\ \\ V = \pi [8(\dfrac{\pi}{3})  - 2 \  tan (\dfrac{\pi}{3}) ]

\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}

7 0
3 years ago
We want to find the zeros of this polynomial: p(x)=5x^3-5x^2-10xp(x)=5x 3 −5x 2 −10x
butalik [34]

Answer:

x = -1, 0, 2

Step-by-step explanation:

p(x) = 5x³ − 5x² − 10x

Factor the greatest common factor:

p(x) = 5x (x² − x − 2)

Now factor the quadratic. You can use the AC method, the quadratic formula, the rational root test, or trial and error.

p(x) = 5x (x − 2) (x + 1)

Finally, set each factor equal to 0 and solve for x.

5x = 0 → x = 0

x − 2 = 0 → x = 2

x + 1 = 0 → x = -1

7 0
2 years ago
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